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Zorglub   Denmark. Jun 12 2012 21:58. Posts 2870

Nice, but a bit confusing An object travelling at negative velocity equals an object travelling faster than light equals an object going back in time.

I started out with nothing and I still got most of it leftLast edit: 12/06/2012 22:10

palak   United States. Jun 12 2012 22:02. Posts 4601

yep...relativity and quantum mechanics is confusing but awesome

dont tap the glass...im about ready to take a fucking hammer to the aquarium 

Zorglub   Denmark. Jun 12 2012 22:10. Posts 2870


  On June 12 2012 21:02 palak wrote:
yep...relativity and quantum mechanics is confusing but awesome



But does it make any sense saying that speed is independent of the observer, if time is dependent on the observer, and time is used to measure the speed?

"Nature can produce even larger particle energies. Some particles striking the Earth's upper atmosphere have energies that exceed 2*1020 eV. If such particles are protons (with mass of about 1 GeV), their speeds would be 0.999 999 999 999 999 999 999 995 c. For them, &#947; is 1011. Now the age of the universe is about 13 billion years for us, but for such particles, the age of the universe would be about (13 billion years/1011), ie about a month. Such a particle could cross the visible universe in a matter of months (their time)."

I started out with nothing and I still got most of it leftLast edit: 12/06/2012 22:14

palak   United States. Jun 12 2012 22:54. Posts 4601

amount at which spacetime is warped changes based off a persons speed...by some math i don't feel like understanding right now..it happens that objects going at light speed will warp spacetime in the observers reference frame in such a way that it always appears to be traveling at c

  The consequence of Einstein's two postulates are radical: time and space become intertwined in surprising ways. Events that may be simultaneous for one observer can occur at different times for another. This leads to length contraction and time dilation, the slowing down of time in a moving frame. Every observer has her own personal time, caller proper time. That is the time measured by a clock at the observer's location. Two observers, initially the same age as given by their proper times, could have different ages when they met again after traveling along different spacetime paths.
...
Proper Time of Moving Observers

As noted above the proper time is the time measured by a clock at an observer's location. So far we have considered the proper time of a special class of observers, namely, those who are in a fixed spatial location relative to a coordinate system; that is, those for whom dl = 0. But what about the proper time of observers who are moving relative to the coordinate system. How do we compute their proper times? Let's start with the formula for the spacetime interval
ds2 = (cdt)2 - dl2
By dividing throughout by c2 and pulling out a factor of dt2 on the right-hand side we can re-write the interval as
ds2/c2 = dt2[1 - (dl/dt)2/c2].
But, by definition, v = dl/dt is the observer's speed, relative to the coordinate system; so we can write
ds2/c2 = dt2[1 - (v/c)2].
We assume observers can travel only along timelike intervals; therefore, their speed v is always less than the speed of light, c. So in the above expression (v/c)2 is always less than 1. We now take the square root of that expression to obtain:
ds/c = dt[1 - (v/c)2]1/2.
The spacetime interval between two nearby points along the worldline of our moving observer is, by definition, just ds. The latter has the dimensions of distance; but when we divide it by the speed of light we convert ds to a quantity dt = ds/c that has the dimensions of time. Notice that dt = ds/c is always less than or equal to dt. It is only equal to dt when our observer is at rest in the coordinate system. This is the case we considered earlier, when we identified ds/c as the proper time of an observer fixed relative to the coordinate system (that is, dl = 0).
By continuity, we conclude that, in fact, dt = ds/c is the proper time not only for observers at rest in the coordinate system but also for moving observers, provided that they move only along timelike worldlines. This then gives us the rule for computing the proper time of any observer, whether at rest, or in motion, relative to our (arbitrarily chosen) coordinate system: the elapsed proper time between any two nearby events, along the worldline of an observer (regardless of their state of motion) is just the spacetime interval between the nearby points divided by the speed of light:

dt2 = (ds/c)2 = dt2 - (dl/c)2
By adding up (that is, integrating) all the small elapsed proper times dt along the worldline we can compute the total elapsed proper time measured by a clock attached to any observer. The formula that relates dt to dt shows that the former is always less than or equal to the latter: the clocks of moving observers run slower relative to a clock that is stationary in the coordinate system. This is the famous time dilation effect of relativity theory.
Observers that are fixed in space (dl = 0) have particularly simple worldlines; this makes it easy to compute their elapsed proper times. For more complicated worldlines the calculation is not quite as easy because we then have to worry about displacements both in coordinate time dt as well as in coordinate space dl.

http://www.physics.fsu.edu/courses/sp...3033/Relativity/GeneralRelativity.htm

also see
http://en.wikipedia.org/wiki/Time_dilation
http://en.wikipedia.org/wiki/Length_contraction#Paradoxes

dont tap the glass...im about ready to take a fucking hammer to the aquarium 

taco   Iceland. Jun 13 2012 14:06. Posts 1793


  On June 11 2012 18:25 D_smart_S wrote:
a hair consists of cells which consist of atoms and subatoms and quantum particles. It's the electrical charge of a cell that's measured I think but whatever the details, the thing is that quantum particles communicate instantly.



Could we please just ban this annoying troll already?

Nobody is that stupid.


 
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